• No products in the cart.

Illustrate the law of definite proportions from the following data, 0.32 g of sulphur on burning

Illustrate the law of definite proportions from the following data, 0.32 g of sulphur on burning
Complete Mole Concept Chemistry Course
https://ift.tt/3vMVtUB

Join our telegram group for regular updates and free study material
https://ift.tt/3cmV3NY

Visit our website for complete lesson videos and free video solutions of your doubts
https://ift.tt/3wF2iIY

Illustrate the law of definite proportions from the following data :
(i) 0.32 g of sulphur on burning in air produced 224 ml of SO2 at N.T.P.
(ii) A metal sulphite reacts with a mineral acid to give SO2 gas which contains 50% of sulphur and 50% of oxygen.

Show that the data illustrates the law of multiple proportions,laws of chemical combination,laws of chemical combination class 11,law of multiple proportions class 11,law of multiple proportions chemistry,law of definite,law of definite proportions class 11,law of definite and multiple proportions,law of constant proportion,law of reciprocal proportions class 11,law of reciprocal proportion,mole concept one shot,mole concept one shot jee,mole concept chemistry,mole concept chemistry class 11,mole concept one shot neet

#mole_concept #doctorlogics #laws_of_chemical_combination
https://youtu.be/5ez40HlEUm4
Doctor Logics Chemistry IIT JEE NEET
via IFTTT

0 responses on "Illustrate the law of definite proportions from the following data, 0.32 g of sulphur on burning"

Leave a Message

Your email address will not be published.

top
Copyright content © Doctor Logics. All rights reserved.
X